typescript/no-unnecessary-type-constraint Suspicious ​
What it does ​
Disallow unnecessary constraints on generic types.
Why is this bad? ​
Generic type parameters (<T>) in TypeScript may be "constrained" with an extends keyword. When no extends is provided, type parameters default a constraint to unknown. It is therefore redundant to extend from any or unknown.
Example ​
typescript
interface FooAny<T extends any> {}
interface FooUnknown<T extends unknown> {}
type BarAny<T extends any> = {};
type BarUnknown<T extends unknown> = {};
class BazAny<T extends any> {
quxAny<U extends any>() {}
}
const QuuxAny = <T extends any>() => {};
function QuuzAny<T extends any>() {}